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Classical electron radius is $\Delta x =2.82\times 10^{-15} m$ (see this).  Let’s say we are in an $S^4(1/h)$ universe, so in terms of diameter of the universe this is $\Delta x = 1.86 \times 10^{-48} \cdot R_{universe}$.

So we might consider that this corresponds to the $n=10^{48}$-th eigenspinor of the Dirac operator on $S^3(1/h)$, whose eigenvalue is $h n=2.82 \times 10^{-15}$.

If we assume that the Dirac eigenvalues are energy, then we can solve for mass:

$mc^2 = 2.82\times 10^{-15}$

and

$m = 3.13 \times 10^{-32} kg$

The measured mass of electron is $m_e = 9.1\times 10^{-31} kg$, which is off by a factor of 30.